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9u^2+26u-3=0
a = 9; b = 26; c = -3;
Δ = b2-4ac
Δ = 262-4·9·(-3)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-28}{2*9}=\frac{-54}{18} =-3 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+28}{2*9}=\frac{2}{18} =1/9 $
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